5x^2/3y-1=12

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Solution for 5x^2/3y-1=12 equation: 


x in (-oo:+oo)

((5*x^2)/3)*y-1 = 12 // - 12

((5*x^2)/3)*y-12-1 = 0

5/3*x^2*y = 13 // : 5/3*y

x^2 = 39/5*y^-1

x^2 = 39/5*y^-1 // ^ 1/2

abs(x) = (39/5)^(1/2)*y^(-1/2)

x = (39/5)^(1/2)*y^(-1/2) or x = -((39/5)^(1/2)*y^(-1/2))

x in { (39/5)^(1/2)*y^(-1/2), -((39/5)^(1/2)*y^(-1/2)) }

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